<p>提供的解决方案中断,不考虑此请求:</p>
<blockquote>
<p>(if they exist)</p>
</blockquote>
<p>这是:</p>
<pre><code>test_dict = {0: [7110, 7000, 8800, 11000, 15000], 1:[7590, 7000, 8800, 11000, 15000], 2:[7080, 7000, 8800, 11000, 15000], 3:[7620, 7000, 8800, 11000, 15000], 4:[7050, 7000, 8800, 11000, 15000], 5:[7590, 7000, 8800, 11000, 15000], 6:[6990, 7000, 8800, 11000, 15000], 7:[7400, 7000, 8800, 11000, 15000], 8:[2760, 3000, 3800, 4800, 6000, 8500], 9:[2730, 3000, 3800, 4800, 6000, 8500]}
for idx, list_ in test_dict.items():
if 0 <= idx <= 9:
test_dict[idx] = list_[1:]
try:
for i in range(1 if idx <= 7 else 2):
test_dict[idx][i] += 1000 if idx <= 7 else 2500
except IndexError:
pass
print(test_dict)
</code></pre>
<p>如果您确定输入大小为10,我们可以进一步简化为:</p>
<pre><code>test_dict = {0: [7110, 7000, 8800, 11000, 15000], 1:[7590, 7000, 8800, 11000, 15000], 2:[7080, 7000, 8800, 11000, 15000], 3:[7620, 7000, 8800, 11000, 15000], 4:[7050, 7000, 8800, 11000, 15000], 5:[7590, 7000, 8800, 11000, 15000], 6:[6990, 7000, 8800, 11000, 15000], 7:[7400, 7000, 8800, 11000, 15000], 8:[2760, 3000, 3800, 4800, 6000, 8500], 9:[2730, 3000, 3800, 4800, 6000, 8500]}
for idx, list_ in test_dict.items():
test_dict[idx] = list_[1:]
try:
for i in range(1 if idx <= 7 else 2):
test_dict[idx][i] += 1000 if idx <= 7 else 2500
except IndexError:
pass
print(test_dict)
</code></pre>
<p>还要注意,您的示例输出并没有忽略前两个元素,而是忽略了一个元素,所以我就是这么做的。如果我们忽略您提到的前两项:</p>
<pre><code>test_dict = {0: [7110, 7000, 8800, 11000, 15000], 1:[7590, 7000, 8800, 11000, 15000], 2:[7080, 7000, 8800, 11000, 15000], 3:[7620, 7000, 8800, 11000, 15000], 4:[7050, 7000, 8800, 11000, 15000], 5:[7590, 7000, 8800, 11000, 15000], 6:[6990, 7000, 8800, 11000, 15000], 7:[7400, 7000, 8800, 11000, 15000], 8:[2760, 3000, 3800, 4800, 6000, 8500], 9:[2730, 3000, 3800, 4800, 6000, 8500]}
for idx, list_ in test_dict.items():
if 0 <= idx <= 9:
test_dict[idx] = list_[1 if idx <= 7 else 2:]
try:
for i in range(1 if idx <= 7 else 2):
test_dict[idx][i] += 1000 if idx <= 7 else 2500
except IndexError:
pass
print(test_dict)
</code></pre>
<p>如果您确定输入大小为10,我们可以进一步简化为:</p>
<pre><code>test_dict = {0: [7110, 7000, 8800, 11000, 15000], 1:[7590, 7000, 8800, 11000, 15000], 2:[7080, 7000, 8800, 11000, 15000], 3:[7620, 7000, 8800, 11000, 15000], 4:[7050, 7000, 8800, 11000, 15000], 5:[7590, 7000, 8800, 11000, 15000], 6:[6990, 7000, 8800, 11000, 15000], 7:[7400, 7000, 8800, 11000, 15000], 8:[2760, 3000, 3800, 4800, 6000, 8500], 9:[2730, 3000, 3800, 4800, 6000, 8500]}
for idx, list_ in test_dict.items():
test_dict[idx] = list_[1 if idx <= 7 else 2:]
try:
for i in range(1 if idx <= 7 else 2):
test_dict[idx][i] += 1000 if idx <= 7 else 2500
except IndexError:
pass
print(test_dict)
</code></pre>