反转字符串的第一和第二部分，并将它们一起返回

Question

如何定义一个函数，将字符串拆分为两个部分，并将其反转？如果字符串为奇数，则保留中间字符（余数）

例如：

revStr(“ “)
revStr(“xy“)
revStr(“wxyz“)
revStr(“vwxyz“)
revStr(“uvwxyz“)
revStr(“tuvwxyz”)

将输出：

xy
xwzy
wvxzy
wvuzyx
vutwzyx

我已经试过了，但我甚至不能让偶数字符串正确翻转

def revStr(string):
    output = " "
    start = 0 
    if len (string) % 2 == 0:
        x = string[start:start//2] 
        y = x[::-1]
        string = x+y
    return(string)
    
printrevStr("abcdef")

需要一些指导或想法，提前感谢！如果有什么我可以澄清的，请告诉我

Answer 1

def reverse_string(string):
    length = len(string)
    
    mid = length//2
    # seperating in 3 parst
    first_half, second_half, middle = None, None, None
    
    # seperating string into first half, second half and mid based on length
    if length%2==1:
        first_half = string[:mid]
        second_half = string[mid+1:]
        middle = string[mid]
    else:
        first_half = string[:mid]
        second_half = string[mid:]
        
    # reversing the first half and second half
    first_half_reverse = first_half[::-1]
    second_half_reverse = second_half[::-1]
    
    # assembling the final result together
    final_result = None
    if middle is not None:
        final_result = first_half_reverse + middle + second_half_reverse
    else:
        final_result = first_half_reverse + second_half_reverse
    
    return final_result