有没有办法像反序函数那样拥有动态的循环数?
字母是字符['a','b','c','d']
和
letterdict是一本字典{'a':['b','c'],'b':['a'],'c':['d'],'d':['b','c','d']
我的代码是n=13的:
for x in letters:
for k1 in letterdict[x]:
for k2 in letterdict[k1]:
for k3 in letterdict[k2]:
for k4 in letterdict[k3]:
for k5 in letterdict[k4]:
for k6 in letterdict[k5]:
for k7 in letterdict[k6]:
for k8 in letterdict[k7]:
for k9 in letterdict[k8]:
for k10 in letterdict[k9]:
for k11 in letterdict[k10]:
for k12 in letterdict[k11]:
for k13 in letterdict[k12]:
word=""
word=x+k1+k2+k3+k4+k5+k6+k7+k8+k9+k10+k11+k12+k13
print(word)
但我希望n个循环使用相同的代码 像这样:
对于n=3
for x in letters:
for k1 in letterdict[x]:
for k2 in letterdict[k1]:
for k3 in letterdict[k2]:
word=""
word=x+k1+k2+k3
print(word)
通常,当您发现自己需要无限多个嵌套循环时,应该编写一个递归函数。以下是作为生成器函数的实现:
示例:请注意,您不必使用字符列表,因为字符串也是字符序列
相关问题 更多 >
编程相关推荐