我有两个数据帧。两者都有两列。我想使用wmd为列source_label
中的每个实体找到与列target_label
中的实体最接近的匹配项。但是,在最后,我希望有一个数据框,其中包含所有4列与实体相关的数据
,source_Label,source_uri
'neuronal ceroid lipofuscinosis 8',"http://purl.obolibrary.org/obo/DOID_0110723"
'autosomal dominant distal hereditary motor neuronopathy',"http://purl.obolibrary.org/obo/DOID_0111198"
,target_label,target_uri
'neuronal ceroid ',"http://purl.obolibrary.org/obo/DOID_0110748"
'autosomal dominanthereditary',"http://purl.obolibrary.org/obo/DOID_0111110"
,source_label, target_label, source_uri, target_uri, wmd score
'neuronal ceroid lipofuscinosis 8', 'neuronal ceroid ', "http://purl.obolibrary.org/obo/DOID_0110723", "http://purl.obolibrary.org/obo/DOID_0110748", 0.98
'autosomal dominant distal hereditary motor neuronopathy', 'autosomal dominanthereditary', "http://purl.obolibrary.org/obo/DOID_0111198", "http://purl.obolibrary.org/obo/DOID_0111110", 0.65
dataframe太大了,我正在寻找一些更快的方法来迭代这两个标签列。到目前为止,我试过:
list_distances = []
temp = []
def preprocess(sentence):
return [w for w in sentence.lower().split()]
entity = df1['source_label']
target = df2['target_label']
for i in tqdm(entity):
for j in target:
wmd_distance = model.wmdistance(preprocess(i), preprocess(j))
temp.append(wmd_distance)
list_distances.append(min(temp))
# print("list_distances", list_distances)
WMD_Dataframe = pd.DataFrame({'source_label': pd.Series(entity),
'target_label': pd.Series(target),
'source_uri': df1['source_uri'],
'target_uri': df2['target_uri'],
'wmd_Score': pd.Series(list_distances)}).sort_values(by=['wmd_Score'])
WMD_Dataframe = WMD_Dataframe.reset_index()
首先,这段代码工作得不好,因为其他两列直接来自dfs,没有考虑实体与uri的关系。 当实体以百万计时,如何使其更快。提前谢谢
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