擅长:python、mysql、java
<p>根据您关于项目存储在变量(即列表)中的评论,以下是一种可能的解决方案:</p>
<pre><code># An example of a stock list you might have
carlist = ["Ferrari", "Ferrari", "Ferrari", "Lambo", "Lambo", "Mustang"]
for car in carlist:
if car in cardict:
cardict[car]['Carcount'] += 1
print(cardict)
</code></pre>