如何使用传递参数在pycharm中运行python程序?

2024-09-30 06:27:08 发布

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我目前在pycharm中运行python程序时遇到问题,我通常都是右键单击并运行程序。我想这样运行程序:

python hrllo.py rahulkapoo vit university

以下是我得到的错误:

Traceback (most recent call last):
  File "C:/Users/rahul/PycharmProjects/untitled/hrllo.py", line 107, in <module>
    aggregate()
  File "C:/Users/rahul/PycharmProjects/untitled/hrllo.py", line 88, in aggregate
    br = login()
  File "C:/Users/rahul/PycharmProjects/untitled/hrllo.py", line 23, in login
    response = br.open('https://academics.vit.ac.in/student/stud_login.asp')
  File "C:\Python27\lib\site-packages\mechanize\_mechanize.py", line 203, in open
    return self._mech_open(url, data, timeout=timeout)
  File "C:\Python27\lib\site-packages\mechanize\_mechanize.py", line 255, in _mech_open
    raise response
mechanize._response.httperror_seek_wrapper: HTTP Error 403: request disallowed by robots.txt

Process finished with exit code 1

Tags: inpy程序responselineloginopenusers
1条回答
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1楼 · 发布于 2024-09-30 06:27:08

在PyCharm中,右键单击脚本(或者在打开脚本的编辑器窗口中,单击Create 'scriptname',将参数放入顶部附近的Script Parameters框中,然后单击OK。在

新的run配置将出现在Pycharm顶部的run按钮的左侧(至少在我的版本中是这样)。现在确保在运行脚本时列出了新的run config。在

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