从python中的单个csv文件创建嵌套词典列表

2024-07-03 06:28:23 发布

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我有一个具有以下结构的csv文件:

team,tournament,player
Team 1,spring tournament,Rebbecca Cardone
Team 1,spring tournament,Salina Youngblood
Team 1,spring tournament,Catarina Corbell
Team 1,summer tournament,Cara Mejias
Team 1,summer tournament,Catarina Corbell
...
Team 10, spring tournament,Jessi Ravelo

我想创建一个嵌套字典(团队、锦标赛),其中包含玩家字典列表。期望的结果是:

{'data': 
   {Team 1:
       {'spring tournament': 
               {'players': [
                   {name: Rebecca Cardone}, 
                   {name: Salina Youngblood},
                   {name: Catarina Corbell}]
        },
        {'summer tournament': 
               {'players': [
                   {name: Cara Mejias}, 
                   {name: Catarina Corbell}]
               }
        }

   },
    ...
  {Team 10:
       {'spring tournament': 
               {'players': [
                   {name: Jessi Ravelo}]
                }
       }
   }
}

我一直在努力把它格式化成这样。我已经能够成功地嵌套第一级(团队-->;锦标赛),但我无法嵌套第二级。目前,我的代码如下所示:

d = {}
header = True
with open("input.csv") as f:
    for line in f.readlines():
        if header:
            header = False
            continue
        team, tournament, player = line.strip().split(",")
        d_team = d.get(team,{})
        d_tournament = d_team.get(tournament, {})
        d_player = d_tournament.get('player',['name'])
        d_player.append(player)
        d_tournament['player'] = d_tournament
        d_team[tournament] = d_tournament
        d[team] = d_team
print(d)

修复代码以便创建嵌套字典的下一步是什么


Tags: csvnameget字典teamheaderplayersummer
3条回答

您描述的示例字典是不可能的(如果您希望在键“Team 1”下有多个字典,请将它们放在列表中),但此代码段:

if __name__ == '__main__':
    your_dict = {}
    with open("yourfile.csv") as file:
        all_lines = file.readlines()

    data_lines = all_lines[1:]  #  Skipping "team,tournament,player" line

    for line in data_lines:
        line = line.strip()  # Remove \n
        team, tournament_type, player_name = line.split(",")
        team_dict = your_dict.get(team, {})  # e.g. "Team 1"

        tournaments_of_team_dict = team_dict.get(tournament_type, {'players': []})  # e.g. "spring_tournament"

        tournaments_of_team_dict["players"].append({'name': player_name})

        team_dict[tournament_type] = tournaments_of_team_dict
        your_dict[team] = team_dict

    your_dict = {'data': your_dict}

对于本例yourfile.csv

team,tournament,player
Team 1,spring tournament,Rebbecca Cardone
Team 1,spring tournament,Salina Youngblood
Team 2,spring tournament,Catarina Corbell
Team 1,summer tournament,Cara Mejias
Team 2,summer tournament,Catarina Corbell

提供以下信息:

{
  "data": {
    "Team 1": {
      "spring tournament": {
        "players": [
          {
            "name": "Rebbecca Cardone"
          },
          {
            "name": "Salina Youngblood"
          }
        ]
      },
      "summer tournament": {
        "players": [
          {
            "name": "Cara Mejias"
          }
        ]
      }
    },
    "Team 2": {
      "spring tournament": {
        "players": [
          {
            "name": "Catarina Corbell"
          }
        ]
      },
      "summer tournament": {
        "players": [
          {
            "name": "Catarina Corbell"
          }
        ]
      }
    }
  }
}

Process finished with exit code 0

您的实现中存在一些问题:

  • 你可以d_player = d_tournament.get('player',['name'])。但实际上,您希望获得名为players的键,这应该是一个字典列表。这些词典的格式必须为{"name": "Player's Name"}。所以你想要 l_player = d_tournament.get('players',[])(默认为空列表),然后执行l_player.append({"name": player})(我将其重命名为l_player,因为它是一个列表,而不是dict)
  • 你可以d_tournament['player'] = d_tournament。我猜你的意思是d_tournament['player'] = d_player
  • 去除行中元素的空白。Doteam, tournament, player = (word.strip() for word in line.split(","))

在进行这些更改后,代码可以正常工作


我强烈建议您使用csv.reader类来读取CSV文件,而不是手动用逗号分隔行

此外,由于python的容器(列表和字典)包含对其内容的引用,您只需添加容器一次,然后使用mydict["key"] = valuemylist.append()对其进行修改,这些更改也将反映在父容器中。由于这种行为,您不需要像使用d_team[tournament] = d_tournament一样在循环中重复分配这些内容

allteams = dict()
hasHeader = True
with open("input.csv") as f:
    csvreader = csv.reader(f)
    if hasHeader: next(csvreader) # Consume one line if a header exists

    # Iterate over the rows, and unpack each row into three variables
    for team_name, tournament_name, player_name in csvreader:
        # If the team hasn't been processed yet, create a new dict for it
        if team_name not in allteams:
            allteams[team_name] = dict()

        # Get the dict object that holds this team's information
        team = allteams[team_name]

        # If the tournament hasn't been processed already for this team, create a new dict for it in the team's dict
        if tournament_name not in team:
            team[tournament_name] = {"players": []}

        # Get the tournament dict object
        tournament = team[tournament_name]

        # Add this player's information to the tournament dict's "player" list
        tournament["players"].append({"name": player_name})

# Add all teams' data to the "data" key in our result dict
result = {"data": allteams}
print(result)    

这给了我们想要的(美化输出):

{
    'data': {
        'Team 1': {
            'spring tournament': {
                'players': [
                    { 'name': 'Rebbecca Cardone' },
                    { 'name': 'Salina Youngblood' },
                    { 'name': 'Catarina Corbell' }
                ]
            },
            'summer tournament': {
                'players': [
                    { 'name': 'Cara Mejias' },
                    { 'name': 'Catarina Corbell' }
                ]
            }
        },
        'Team 10': {
            ' spring tournament': {
                'players': [
                    { 'name': 'Jessi Ravelo' }
                ]
            }
        }
    }
}

也许我忽略了什么,但你不能用:

df.groupby(['team','tournament'])['player'].apply(list).reset_index().to_json(orient='records')

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