我试图将前两列中有NaNs
的行移到左边,这样右边的值就填满了这一列。以下是我目前正在尝试做的事情:
(注意:match
数据帧是从以下链接下载的:https://www.kaggle.com/hugomathien/soccer)
#original dataframe
<class 'pandas.core.frame.DataFrame'>
Int64Index: 21374 entries, 145 to 25978
Data columns (total 47 columns):
id 21374 non-null int64
country_id 21374 non-null int64
league_id 21374 non-null int64
season 21374 non-null object
stage 21374 non-null int64
date 21374 non-null object
match_api_id 21374 non-null int64
home_team_api_id 21374 non-null int64
away_team_api_id 21374 non-null int64
home_team_goal 21374 non-null int64
away_team_goal 21374 non-null int64
goal 13325 non-null object
shoton 13325 non-null object
shotoff 13325 non-null object
foulcommit 13325 non-null object
card 13325 non-null object
cross 13325 non-null object
corner 13325 non-null object
possession 13325 non-null object
BSA 11856 non-null float64
Home Team 21374 non-null object
Away Team 21374 non-null object
League 21374 non-null object
Country 21374 non-null object
home_player_1 21374 non-null object
home_player_2 21374 non-null object
home_player_3 21374 non-null object
home_player_4 21374 non-null object
home_player_5 21374 non-null object
home_player_6 21374 non-null object
home_player_7 21374 non-null object
home_player_8 21374 non-null object
home_player_9 21374 non-null object
home_player_10 21374 non-null object
home_player_11 21374 non-null object
away_player_1 21374 non-null object
away_player_2 21374 non-null object
away_player_3 21374 non-null object
away_player_4 21374 non-null object
away_player_5 21374 non-null object
away_player_6 21374 non-null object
away_player_7 21374 non-null object
away_player_8 21374 non-null object
away_player_9 21374 non-null object
away_player_10 21374 non-null object
away_player_11 21374 non-null object
winner 21374 non-null object
dtypes: float64(1), int64(9), object(37)
memory usage: 7.8+ MB
创建数据帧
columns = match.columns[match.columns.get_loc('home_player_1'):match.columns.get_loc('away_player_1')+1].values
columns = list(columns)
player_appearences = match.groupby(columns[0]).size().reset_index()
player_appearences.rename(columns = {0:"Count_{}".format(player_appearences.columns[0][len(player_appearences.columns[0])-1])}, inplace = True, errors='raise')
player_appearences
for i in range(1,12):
player_appearences2 = match.groupby(columns[i]).size().reset_index()
player_appearences2
player_appearences2.rename(columns = {0:"Count_{}".format(player_appearences2.columns[0][len(player_appearences2.columns[0])-1])}, inplace = True, errors='raise')
player_appearences = player_appearences.merge(right = player_appearences2,how="outer",left_on ="{}".format(player_appearences.columns[0]),right_on = "{}".format(player_appearences2.columns[0]))
player_appearences
#overwrite nans in first column with names in current [i] player column
#select rows where first two columns give nan values
player_appearences.loc[(player_appearences.loc[:,"home_player_1"].isna()==True) & (player_appearences.loc[:,"Count_1"].isna()==True),["home_player_1","Count_1"]] = player_appearences.loc[(player_appearences.loc[:,"home_player_1"].isna()==True) & (player_appearences.loc[:,"Count_1"].isna()==True),["home_player_2","Count_2"]]
然后,当我打印player_appearences
时,数据帧保持不变。我不确定它是没有做任何事情,还是正在创建原始数据帧的副本。有人能告诉我为什么这不起作用/如果有更好的方法,建议一个更好的方法吗
可以使用
shift(-1, axis=1)
移动列,使用df[df.home_player_1.isna() & df.Count_1.isna()]
指定要影响的行。移动的行应该在数据帧中重写使用^{} ,那么您只需要^{} (} :
dropna = True
默认情况下)+^{或^{} 与^{} :
细节
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