如果子字符串位于另一个子字符串之前，则忽略该子字符串

Question

我有一个字符串，正在寻找两个子字符串，希望显示这两个子字符串之间的内容。但是我想在子串2之前找到子串1。在找到子字符串1之前，如何忽略子字符串2？我遇到的问题是，如果subString2位于substring1之前，它将返回一个空列表

def findMiddle(mainString, subString1, subString2):
 
    newString = []
    startPos = mainString.find(subString1)
    endPos = mainString.find(subString2)
        
    for i in range(startPos, endPos):
            newString.append(i)
            
    return newString

Answer 1

def middle(line: str, word1: str, word2: str) -> str:
    i = line.find(word1)
    if i >= 0:
        j = line.find(word2, i + len(word1))
        if j > i:
            return line[i + len(word1):j].strip()
    return None

print(middle("a b c", "a", "c"))
print(middle("c b a", "a", "c"))

b

None

Answer 2

不要在整个字符串中搜索结束位置，只搜索开始位置后的字符串片段

startPos = mainString.find(subString1)
endPos = startPos+mainString[startPos:].find(subString2)

Answer 3

下面是完整的代码，可以帮助您了解哪里出了问题。我把返回函数留给你去解密。你很容易弄明白。如果你觉得困难，请告诉我

搜索字符串时，索引很重要。此外，您还需要检查在未找到第一个字符串但找到第二个字符串时的条件。记住，如果找不到字符串，find方法将返回-1。在检查下一个字符串之前，需要先检查该字符串

mainString = 'Happy Thanksgiving to everyone this morning'
subString1 = 'Thanks'
subString2 = 'is'
def findMiddle(mainString, subString1, subString2):
    x = mainString.find(subString1)
    if x < 0:
        print (subString1, 'does not exist in', mainString)
        return
    ln = len(subString1)
    y = mainString.find(subString2,x+ln)
    if y < 0: 
        print (subString2, 'does not exist in', mainString, 'after', subString1)

    elif y == x+ln:
        #find result will always be pos of string 
        #irrespective of where you start from. 
        #So you need to check if pos is after previous find

        print ('No strings exist in', mainString, 'between', subString1, 'and', subString2)

    else:
        print ('The middle string between',subString1,'and',subString2, ':',mainString[x+ln:y])


findMiddle(mainString, subString1, subString2)

程序的输出如下所示：

例1：

mainString = 'Happy Thanksgiving to everyone this morning'
subString1 = 'Thanks'
subString2 = 'is'

输出：

The middle string between Thanks and is : giving to everyone th

例2：

mainString = 'Happy Thanksgiving to everyone this morning'
subString1 = 'Thaxks'
subString2 = 'is'

输出：

Thaxks does not exist in Happy Thanksgiving to everyone this morning

例3：

mainString = 'Happy Thanksgiving to everyone this morning'
subString1 = 'Thanks'
subString2 = 'ix'

输出：

ix does not exist in Happy Thanksgiving to everyone this morning after Thanks

例4：

mainString = 'Happy Thanksgiving to everyone this morning'
subString1 = 'Thanks'
subString2 = 'Happy'

输出：

Happy does not exist in Happy Thanksgiving to everyone this morning after Thanks

例5：

mainString = 'Happy Thanksgiving to everyone this morning'
subString1 = 'Thanks'
subString2 = 'giv'

输出：

No strings exist in Happy Thanksgiving to everyone this morning between Thanks and giv