擅长:python、mysql、java
<p>假设列表项是路径:</p>
<pre><code>import os
paths = [
'/dbfs/mnt/abc/date=20210225/fsp_store_abcxyz_lmn_',
'/dbfs/mnt/abc/date=20210225/fsp_store_schu_lev_bsd_s_'
]
for path in paths:
print(os.path.basename(path))
</code></pre>
<p>出去</p>
<pre><code>fsp_store_abcxyz_lmn_
fsp_store_schu_lev_bsd_s_
</code></pre>
<p><code>os.path.basename</code>:<a href="https://docs.python.org/3/library/os.path.html#os.path.basename" rel="nofollow noreferrer">https://docs.python.org/3/library/os.path.html#os.path.basename</a></p>
<p>这个函数非常好,因为您不必指定路径分隔符。[<code>\\</code>或<code>/</code>]</p>