如何在Python中找到最小值的索引？

Question

因此，我在第50行中使用val = np.argmin(R_abs)找到了数组中的最低值，但现在我试图找到该值的索引。我尝试在第52行中使用val_index = [idx for idx, minval in enumerate(R_abs) if minval == val]，但得到了一个空数组。我做错了什么？我相信.list（）只适用于list。R_abs是一个数组

R_abs = abs(R-atm_tropo)
val = np.argmin(R_abs) # (line 50)
# val_index = np.where(R_abs == val)
val_index = [idx for idx, minval in enumerate(R_abs) if minval == val] # (line 52)

Answer 1

更新了NumPy数组而不是Python列表：

This article建议您使用np.where：

import numpy as np
# Create a numpy array from a list of numbers
arr = np.array([11, 12, 13, 14, 15, 16, 17, 15, 11, 12, 14, 15, 16, 17])# Get the index of elements with value 15
result = np.where(arr == 15)
print('Tuple of arrays returned : ', result)
print("Elements with value 15 exists at following indices", result[0], sep='\n')

返回

Tuple of arrays returned :  (array([ 4,  7, 11], dtype=int32),)
Elements with value 15 exists at following indices
[ 4  7 11]