擅长:python、mysql、java
<p>首先使用整数除法将其设置在第一个位置:</p>
<pre class="lang-py prettyprint-override"><code>a = 1234
n = 3
b = ( a // 10**(n-1) ) % 10 # 2
</code></pre>
<p><code>n</code>是您要检索的位置</p>
<pre><code>n = 1 > 10^0 = 1 > 1234 // 1 = 1234 > b = 1234 % 10 = 4
n = 2 > 10^1 = 10 > 1234 // 10 = 123 > b = 123 % 10 = 3
n = 3 > 10^2 = 100 > 1234 // 100 = 12 > b = 12 % 10 = 2
n = 4 > 10^3 = 1000 > 1234 // 1000 = 1 > b = 1 % 10 = 1
</code></pre>