Python中的跳转打印

Question

我不知道这个调用方法的名称， 这是我的简单python代码

fruits1 = ["banana","avocado","grape","orange","strawberry"]
for a in fruits1:
 print(a)

如果正常，打印（a）输出如下

banana
avocado
grape
orange
strawberry

那么，如何使输出结果像这样打印（a）

avocado
grape
orange
strawberry

我想跳，第一个结果是鳄梨

谢谢

Answer 1

你可以试试下面的

fruits = ["banana","avocado","grape","orange","strawberry"]
for a in fruits[1:]:
    print(a)

或者，您可以单独列出不打印的项目

fruits = ["banana","avocado","grape","orange","strawberry"]
exclude = ["banana"]
for a in fruits:
    if a not in exclude:
        print(a)

Answer 2

试试这个：

fruits1 = ["banana","avocado","grape","orange","strawberry"]
for a in fruits1[1:]:
    print(a)

Answer 3

试试这个：

for a in fruits1[1:]:
 print(a)