我有一个foo.txt文件,其中包含以下行:
A 10 20 30
B 40 50 60
C 70 80 90
我将这些值转换为弧度并将其转换为旋转矩阵,然后将旋转矩阵与另一个旋转矩阵相乘,并将输出存储在新变量中,然后保存到新的文本文件中
import transforms3d.euler as t3d
import numpy as np
import pandas as pd
# Suppress scientific notation
np.set_printoptions(suppress=True)
file="foo.txt"
r1=np.array([[1,0,0],[0,1,0],[0,0,1]])
r2=np.array([[0.5,-0.30902,-0.80902],[0.30902,-0.80902,0.5],[-0.80902,-0.5,-0.30902]])
r3=np.array([[0.5,0.30902,-0.80902],[-0.30902,-0.80902,-0.5],[-0.80902,0.5,-0.30902]])
R=np.array([r1,r2,r3])
source_array=pd.read_csv(file, sep=" ", header=None)
name_array=source_array.iloc[:,0].to_numpy()
number_array=source_array.iloc[:,1:4].to_numpy()
fullstack=np.empty((1,4))
for i in range(number_array.shape[0]):
inMat=t3d.euler2mat(np.radians(number_array[i][0]),\
np.radians(number_array[i][1]),\
np.radians(number_array[i][2]),'rzyz')
for j in range(R.shape[0]):
expMat=np.dot(inMat,R[j])
expDeg=np.degrees(t3d.mat2euler(expMat))
name=np.repeat(name_array[i],1)
nameandDeg=np.hstack((name,expDeg)).reshape(1,4)
fullstack=np.append(fullstack,nameandDeg,axis=0)
np.savetxt('foo3.txt',fullstack,fmt='%s')
预期产量为
A 10.314104815618196 17.229396562958897 41.56670396614096
A -86.15202640927517 58.81289030540899 101.65925914885956
A 119.58912709295329 73.9812604867084 6.339258927995449
B 45.90468727333836 22.521012118111006 109.63942512488691
B -59.08770198050942 30.43292092265276 177.0466653835958
B -123.45325226252277 66.42599043668275 175.86346970407573
C 80.0 3.455054858914999e-15 160.0
C -63.59253616776351 -9.42984810562947 -140.45406233407002
C -127.56777089055139 26.411096630846163 -143.9360404337779
但是以当前形式运行代码后,在数组的开头会出现一行额外的代码
**0.0** **5e-324** **1e-323** **1.5e-323**
A 10.314104815618196 17.229396562958897 41.56670396614096
A -86.15202640927517 58.81289030540899 101.65925914885956
A 119.58912709295329 73.9812604867084 6.339258927995449
B 45.90468727333836 22.521012118111006 109.63942512488691
B -59.08770198050942 30.43292092265276 177.0466653835958
B -123.45325226252277 66.42599043668275 175.86346970407573
C 80.0 3.455054858914999e-15 160.0
C -63.59253616776351 -9.42984810562947 -140.45406233407002
C -127.56777089055139 26.411096630846163 -143.9360404337779
为什么会出现这条线?我怎样才能摆脱它
还有一个问题,是否有一种方法可以格式化输出,使所有包含浮动的列都表示为%0.3f
提前谢谢
获取行
0.0 5e-324 1e-323 1.5e-323
的原因是因为行fullstack=np.empty((1,4))
。而在数值计算中np.empty(someshape)
会产生有效等于0的条目,将它们保存到文件still writes the in memory numerical value,或:0.0 5e-324 1e-323 1.5e-323
。只需将np.savetxt()
行更改为np.savetxt('foo3.txt',fullstack[1:],fmt='%s')
或者重新思考为什么首先需要创建一个空数组
还请注意,如果在j循环的每次迭代中都要附加到fullstack。您不需要在j循环的每次迭代中保存完整的堆栈,只需在j循环完成后保存一次
np.empty((1,4))
创建给定形状的新数组without initializing entries。这意味着fullstack数组不是空的,甚至在循环中开始向其追加nameandDeg
之前就包含值。当您将fullstack
写入foo3.txt
文件时,您看到的第一行是这些值相关问题 更多 >
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