import re
string = "[key:value, key2:[key2a:val2:a, key2b:[foo:'bar']]]"
d = [i if not i.startswith("'") else i[1:-1] for i in re.findall("[\[\]]|:|'.*?'|\w+|,", string)[1:-1]]
def to_dict(d):
while (n:=next(d, None)) not in {None, ']'}:
_ = next(d)
if (v:=next(d)) == '[':
v = dict(to_dict(d))
else:
c = [v]
while (j:=next(d)) not in {',', ']'}:
c.append(j)
if j == ']':
d = iter([*d, j])
v = ''.join(c)
yield (n, v)
print(dict(to_dict(iter(d))))
def to_dict(d):
n = next(d, None)
while n not in {None, ']'}:
_, v = next(d), next(d)
if v == '[':
v = dict(to_dict(d))
else:
c, j = [v], next(d)
while j not in {',', ']'}:
c.append(j)
j = next(d)
if j == ']':
d = iter([*d, j])
v = ''.join(c)
yield (n, v)
n = next(d, None)
print(dict(to_dict(iter(d))))
可以使用递归生成器函数:
输出:
编辑:不带赋值表达式的解决方案(
:=
walrus运算符):相关问题 更多 >
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