如何打印第二个数字及其位置

Question

我的任务是编写一个脚本，将第二个数字写入s并将其位置写入标准输出

输入示例：

afg 456 gg 677

示例输出：

 677 12

除了print部分之外，我的代码都是正确的-它打印的是第一个数字及其位置，而不是第二个：

s = input()
i = 0

while i < len(s) and (s[i] < "0" or "9" < s[i]):
    i = i + 1

if i < len(s):

    j = i
    while j < len(s) and "0" <= s[j] and s[j] <= "9":
        j = j + 1

    print(s[i:j], len(s[0:i]))

Answer 1

我想这是一个有限制的家庭作业吧？因此，这里有一个愚蠢而有教育意义的例子。只需增加计数器i并再次运行相同的循环：

s = input()
i = 0
j = 0

# looking for the first num
while i < len(s) and (s[i] < "0" or "9" < s[i]): i = i + 1

if i < len(s):
    j = i
    while j < len(s) and "0" <= s[j] and s[j] <= "9":  j = j + 1

# increase counter
i = i + j

# run again for the second num
if i < len(s):
    while i < len(s) and (s[i] < "0" or "9" < s[i]): i = i + 1

    if i < len(s):
        j = i
        while j < len(s) and "0" <= s[j] and s[j] <= "9":  j = j + 1

print(s[i:j], len(s[0:i]))

不是为了现实生活