在句子列表中查找单词列表并返回匹配的句子

Question

从句子列表和单词列表中，仅当所有三个单词都与单词列表（三叉图）匹配时，如何返回句子列表

请建议。下面是示例列表

listwords = [['people','suffering','acute'], ['Covid-19','Corona','like'], ['people','must','collectively']]

listsent = ['The number of people suffering acute hunger could almost double.',
            'Lockdowns and global economic recession have',
            'one more shock – like Covid-19 – to push them over the edge',
            'people must collectively act now to mitigate the impact']

输出列表应位于第一位&；最后的句子，因为它们在listwords中有三个匹配的单词

预期产出为：

['The number of people suffering acute hunger could almost double.',
 'people must collectively act now to mitigate the impact']

Answer 1

欢迎来到堆栈溢出

请尝试以下解决方案：

listwords = [['people','suffering','acute'], ['Covid-19','Corona','like'], ['people','must','collectively']]

listsent = ['The number of people suffering acute hunger could almost double.',
            'Lockdowns and global economic recession have',
            'one more shock – like Covid-19 – to push them over the edge',
            'people must collectively act now to mitigate the impact']

# interate through each sentence
for sentence in listsent:
    # iterate through each group of words
    for words in listwords:
        # check to see if each word group is in the current sentence
        if all(word in sentence for word in words):
            print(sentence)

我对这些行进行了评论，让你了解发生了什么

代码的第一部分遍历列表中的每个句子

for sentence in listsent:

然后我们需要遍历单词列表中的单词组

for words in listwords

这就是事情变得有趣的地方。因为你有嵌套列表，我们需要检查以确保在句子中找到所有三个单词

if all(word in sentence for word in words):

最后，您可以打印出包含所有单词的每个句子

print(sentence)

您还可以将其放入函数中，并将找到的句子作为新列表返回

listwords = [['people','suffering','acute'], ['Covid-19','Corona','like'], ['people','must','collectively']]

listsent = ['The number of people suffering acute hunger could almost double.',
            'Lockdowns and global economic recession have',
            'one more shock – like Covid-19 – to push them over the edge',
            'people must collectively act now to mitigate the impact']


def check_words(listwords, listsent):
    listsent_new = []
    # interate through each sentence
    for sentence in listsent:
        # iterate through each group of words
        for words in listwords:
            # check to see if each word group is in the current sentence
            if all(word in sentence for word in words):
                listsent_new.append(sentence)
    return listsent_new


if __name__ == '__main__':
    print(check_words(listwords, listsent))