擅长:python、mysql、java
<p>以前的anaswer是有效的,但我最终使用了这个:</p>
<pre><code>def findBucket(s3):
for bucket in s3.buckets.all():
if('myKeyWord' in bucket.name):
return bucket.name
return 'notFound'
s3 = boto3.resource('s3')
bucketName = findBucket(s3)
if(bucketName != 'notFound'):
#upload file to that bucket
</code></pre>