为什么我的嵌套while循环不能在python中工作？

Question

所以我正在制作一个摇滚纸牌游戏，我添加了我的源代码。到目前为止，我已经让球员进入他们的选择。我尝试添加一个检查，以确保他们输入的选项是三个选项之一。我的程序修正了一次，然后它停止做任何事情

这是我的源代码

print('''Please pick one of the following:
Rock
Paper
Scissors''')
p1 = None
p2 = None
while True:
    gameDict = {"rock":1,"paper":2,"scissors":3}
    in1 = input("Player 1: ").lower()
    in2 = input("Player 2: ").lower()
    p1 = gameDict.get(in1)
    p2 =gameDict.get(in2)
    while gameDict.get(p1)==None or gameDict.get(p2)==None:
        if(p1==None):
            p1=input("Player 1, please enter one of the choices listed above: ")
        elif p2== None:
            p2=input("Player 2, please enter one of the choices listed above: ")
    print('Done!!')
    print(p1,p2)

Answer 1

您可以将用户（“剪刀”）输入的键与字典中的值进行比较。您需要确保钥匙是正确的：

while in1 not in gameDict:
    in1 = input("Player 1, please...: ").lower()
while in2 not in gameDict:
    in2 = input("Player 2, please...: ").lower()

获得有效输入后，您可以查找它们：

p1 = gameDict[in1]
p2 = gameDict[in2]