擅长:python、mysql、java
<p>我不知道字典中的值是什么意思,所以我将把它签名为x</p>
<pre class="lang-py prettyprint-override"><code>df['x'] = df['Id'].apply(lambda x: dict[str(x)])
df['Earned_normal'] = df.apply(lambda x: x[2]/x[5][x[4]], axis=1) #here may be problem with index cause I kinda wrong imported csv.
</code></pre>