我想在创建记录时向关注者发送cuustom消息 我的班级:
class StockAlert(models.Model): _name = "stock.alert" _inherit = ['mail.thread', 'mail.activity.mixin'] responsable_id = fields.Many2one('res.users' ,store=True) @api.multi def write(self, vals): result = super(StockAlert, self).write(vals) for record in self: followers= [] if record.responsable_id.partner_id.id not in record.message_follower_ids.ids: followers.append(record.responsable_id.partner_id.id) record.message_subscribe(followers) return result @api.model def create(self, vals): result = super(StockAlert, self).create(vals) for record in result: followers= [] if record.responsable_id.partner_id.id not in record.message_follower_ids.ids: followers.append(record.responsable_id.partner_id.id) record.message_subscribe(followers) return result
在我看来,这是一个喋喋不休的话题:
<div class="oe_chatter">
<field name="message_follower_ids" widget="mail_followers"/>
<field name="activity_ids" widget="mail_activity"/>
<field name="message_ids" widget="mail_thread"/>
</div>
请帮忙
我不完全确定追随者订阅是否正确,但发布消息应该很容易。订阅后立即执行以下操作:
查看
message_post
的定义,以获得更多可能的参数,如subject
或partner_ids
partner_ids
可能会让您感兴趣,因为此参数可用于自动订阅message_post
。例如在create
中:相关问题 更多 >
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