擅长:python、mysql、java
<p>也许这个解决方案会变得更简单</p>
<pre class="lang-py prettyprint-override"><code>def test(a):
dict_word={
'a':'@'
,'e':'#'
,'i':'%'
,'o':'*'
}
b=a[::-1]
print(b)
new_word = ''
c = []
for i in b:
if i in dict_word:
res = dict_word[i]
else:
res=i
c.append(res)
new_word=''.join(c)
return new_word
a='sdocisae'
b=test(a)
print(b)
```
</code></pre>