<p>只要加上一些额外的支票</p>
<pre><code>sequence="GATCTCTATACCAACTCAAAATGAAGACTCTTCTTTACACTTTCGAGCTCAGCAGGCTTACCGAGAAGAGTCGTCGTTCACATCCCCCCCTGTGCGAGATCAAGAAATTTGGCGACGTCGGCTTATTATCCTCCGCTGTCAATCAGTTGGACACATCTCTCCGGTCACTGCCGGACAAGCCAACCGAAGATTCGATTCTTCAGCAGCTTATCGACATTGCTGGTGGTGAAAAGCCAAGGCACAGCATCATAGTTGCGACCAATACGTCATACGACCGAGAGACATTGGTAAAGATCCTTCAACGATTCCCATACACCATACCTGGTCTGTCAGATTCAGGCTTGGAATCAGAAACACTCGAGGCTCTTGAGCACATCGCTTTTGCATTAGCCGGGCGATTAGCTCATAGATTTGACTACGGGTTCAATCCAGAGGCCAGTATCGTTCAACACCTCGAGATGTTCACCACCCTTTGGCACCAAAGATCTGCATTACCACCTGCGCCTGCCCCGTATCGACTTCCCGTTCCCGTCAATCAAGGAAGAGTCTCCTCATCAGATGATGGCTCTGATACTGAGTCAGAACTGGATGAAAAATACCACAACATCAAGAAGTCAGGACTTTGGAGGTTTCTGGATATGTTCAAAATGAACTTCAAGAGGTCTTAGATAACGGTCTAGTTCTAGTTCTGCAACTCACACTGA"
print(len(sequence))
pairs = {"A":"T", "T":"A", "G":"C", "C":"G"}
ans = []
for i in range(len(sequence) - 9 + 1):
pal = True
for j in range(2):
if pairs[ sequence[i+j] ] != sequence[i+5-j]:
pal = False
break
if not pal:
continue
if (sequence[i+7] == sequence[i+8]) and (sequence[i+7] in ('C', 'G')):
print(sequence[i : i+9])
ans.append(sequence[i : i+9])
else:
print(sequence[i : i+6] + " (X)")
print("Count of answer: %d" % len(ans))
</code></pre>
<p>输出:</p>
<pre><code>704
GATCTC (X)
GAGCTC (X)
GCAGGC (X)
GTTCAC (X)
GAGATC (X)
TCAAGA (X)
AAATTT (X)
GACGTC (X)
CAGTTG (X)
TGGACA (X)
AAGATT (X)
CTTCAG (X)
CCAAGG (X)
CGACCG (X)
TTGGAA (X)
CTCGAG (X)
TCTTGA (X)
CTTGAG (X)
TGAGCA (X)
CGGGCG (X)
ATAGAT (X)
ACGGGT (X)
TCCAGA (X)
CTCGAG (X)
TCGAGA (X)
TGTTCA (X)
GTTCAC (X)
GGCACC (X)
AGATCT (X)
CACCTG (X)
GCCTGCCCC
GACTTC (X)
CAGATG (X)
AGAACT (X)
TCAAGA (X)
GAAGTCAGG
TCAGGA (X)
AGGACT (X)
TCTGGA (X)
TGTTCA (X)
TTCAAA (X)
TCAAGA (X)
GAGGTC (X)
AGGTCT (X)
TAGATA (X)
AGTTCT (X)
AGTTCT (X)
Count of answer: 2
</code></pre>