擅长:python、mysql、java
<p>我还在学习Python的诀窍。但根据so上的<a href="https://stackoverflow.com/a/37645155/9758194">this</a>older帖子,类似于以下内容的内容应该是可行的:</p>
<pre><code>from collections import Counter
listt = [["a","abc","zzz","xxx","abc","abc"],["yyy","ggg","abc","cccc"]]
queryList = ["abc","cccc","abc","yyy"]
OutputList = [len(list((Counter(x) & Counter(queryList)).elements())) for x in listt]
# [2, 3]
</code></pre>
<p>我会留意其他的方法</p>