擅长:python、mysql、java
<pre><code>list1 = ['user01','user01', 'aa-user01','user02','user02', 'user03', 'xyz-user02']
list2 = []
for i in range(0, len(list1)):
if list1[i] not in list2:
list2.append(list1[i])
list2 = list(dict.fromkeys(list2))
print(list2)
</code></pre>
<p>打印(列表2)</p>