字符串和整数组合中缺少字符

Question

到目前为止，我已经创建了一个返回缺少的字符串的函数。我们可以把它和整数混合吗？例如：

输入："3629aghrjlsbwofhe"

输出："014578bcdikmnpqtuvxyz"

字母字符串的当前代码：

def missingCharacters(Str):
    
    MAX_CHAR = 26
    
    x = [False for i in range(MAX_CHAR)]
    

    for i in range(len(Str)):
        if (Str[i] >= 'a' and Str[i] <= 'z'):
            x[ord(Str[i]) - ord('a')] = True
        
    result = ""
 
    for i in range(MAX_CHAR):
        if (x[i] == False):
          result += chr(i + ord('a'))
        
    return result

Answer 1

可以使用一些stringutils和条件生成器表达式执行以下操作：

from string import digits, ascii_lowercase

def missingCharacters(s):
    # if s is long, this will make the repeated membership test O(1)
    # s = set(s)   
    return "".join(c for c in digits + ascii_lowercase if c not in s)

missingCharacters("3629aghrjlsbwofhe")
# '014578cdikmnpqtuvxyz'