擅长:python、mysql、java
<p>您可以尝试:</p>
<pre><code>list_in = {'key0': {'a': ['A', 'B', 'C'], 'b': ['A', 'B', 'C']}, 'key1': {'c': ['A', 'B', 'C'], 'd': ['A', 'B', 'C']}, 'key2': {'e': 0, 'f': 0}}
nth = 1
for k,v in list_in.items():
for k2 in v.keys():
element = list_in[k][k2]
if isinstance(element, list):
list_in[k][k2] = element[nth]
print(list_in)
</code></pre>
<p>它返回:</p>
<pre><code>{'key0': {'a': 'B', 'b': 'B'},
'key1': {'c': 'B', 'd': 'B'},
'key2': {'e': 0, 'f': 0}}
</code></pre>