ValueError：GeoDataFrame的真值不明确。使用a.empty、a.bool（）、a.item（）、a.any（）或a.all（）

Question

我有DataFrame，我想做，这似乎是一个简单的步骤

import pandas as pd

# initialize list of lists
data = [['tom', 10], ['nick', 15], ['juli', 14]]
  
# Create the pandas DataFrame
mydf = pd.DataFrame(data, columns = ['Name', 'Age'])

f = mydf  

if(f == mydf or f == clinic):
    
    print("yes it is ok ")
else:
    print("no its not ok ")

为什么这个小程序会出现以下错误

ValueError：数据帧的真值不明确。使用a.empty、a.bool（）、a.item（）、a.any（）或a.all（）

Answer 1

以下不是解决此问题的最佳方案，但可以作为解决此问题的备选方案：

# Get the name of a DataFrame 
def get_df_name(df):
    name =[x for x in globals() if globals()[x] is df][0]
    return name

f = doctors  ##  GeoDataFrame
f = get_df_name(f)

if(f == "doctors" or f == "clinic"):
    
    print("yes it is ok ")
else:
    print("no its not ok ")

输出：可以

Answer 2

我无法告诉您原因，但是将两个数据帧与==进行比较似乎会触发此错误。您已经找到了一种迂回的方法来防止这种情况，if globals()[x] is df是关键部分the ^{} in particular

在不改变所有逻辑的情况下，进行这种改变就足够了：

import pandas as pd

# initialize list of lists
data = [['tom', 10], ['nick', 15], ['juli', 14]]
  
# Create the pandas DataFrame
mydf = pd.DataFrame(data, columns = ['Name', 'Age'])

f = mydf  

if(f is mydf or f is clinic):
    
    print("yes it is ok ")
else:
    print("no its not ok ")

但是这只是一个创可贴解决方案；考虑这种修改：

import pandas as pd

# initialize list of lists
data = [['tom', 10], ['nick', 15], ['juli', 14]]
  
# Create the pandas DataFrame
mydf = pd.DataFrame(data, columns = ['Name', 'Age'])
mydf2 = pd.DataFrame(data, columns = ['Name', 'Age'])  # a separate but equal dataframe

f = mydf2  

if(f is mydf or f is clinic):
    
    print("yes it is ok ")
else:
    print("no its not ok ")  # output: not its not ok

真正的解决办法是使用^{}：

import pandas as pd

# initialize list of lists
data = [['tom', 10], ['nick', 15], ['juli', 14]]
  
# Create the pandas DataFrame
mydf = pd.DataFrame(data, columns = ['Name', 'Age'])
mydf2 = pd.DataFrame(data, columns = ['Name', 'Age'])

f = mydf2  

if(f.equals(mydf) or f.equals(clinic)):
    
    print("yes it is ok ")  # output: yes it is ok
else:
    print("no its not ok ")