当字符串是多个单词时，将罗马数字转换为WordForm

Question

我创建了下面的函数来将罗马数字转换为单词形式。它按预期工作。如果建筑物/字符串以I-X中的罗马数字结尾，则会将其转换为单词。我知道有一个洞（如果罗马数字不是最后一个字的话）。我想不出如何实现这一点。想法

另外，我对Python还很陌生，所以我很好奇是否有必要清理代码。我觉得它很笨重

def replace_roman_numerals(string):
if len(string.split()) > 1:     # if the community name has more than one word, split the words, else return community as is
    first, *middle, last = string.split()
else:
    first = ""
    middle = ""
    last = ""
w = string.split()  # splits the community name into words
lw = w[len(w)-1]    # returns the last word in the community
# convert RN into a word if the last word in the community is a RN and remove excessive blanks and characters from the middle variable
if lw in ("I", "1"):         return " ".join((first + " " + str(middle)[1:-1].replace("'","").replace(",","") + " One").split())
elif lw in ("II", "2"):      return " ".join((first + " " + str(middle)[1:-1].replace("'","").replace(",","") + " Two").split())
elif lw in ("III", "3"):     return " ".join((first + " " + str(middle)[1:-1].replace("'","").replace(",","") + " Three").split())
elif lw in ("IV", "4"):      return " ".join((first + " " + str(middle)[1:-1].replace("'","").replace(",","") + " Four").split())
elif lw in ("V", "5"):       return " ".join((first + " " + str(middle)[1:-1].replace("'","").replace(",","") + " Five").split())
elif lw in ("VI", "6"):      return " ".join((first + " " + str(middle)[1:-1].replace("'","").replace(",","") + " Six").split())
elif lw in ("VII", "7"):     return " ".join((first + " " + str(middle)[1:-1].replace("'","").replace(",","") + " Seven").split())
elif lw in ("VIII", "8"):    return " ".join((first + " " + str(middle)[1:-1].replace("'","").replace(",","") + " Eight").split())
elif lw in ("IX", "9"):      return " ".join((first + " " + str(middle)[1:-1].replace("'","").replace(",","") + " Nine").split())
elif lw in ("X", "10"):       return " ".join((first + " " + str(middle)[1:-1].replace("'","").replace(",","") + " Ten").split())
else:                 return " ".join((first + " " + str(middle)[1:-1].replace("'","").replace(",","") + " " + lw).split())

投入：

s = "Park III"
s = replace_roman_numerals(s)
print (s)
s = "American Tower - Bldg IV"
print (replace_roman_numerals(s))
s = "Estancia"
print (replace_roman_numerals(s))
s = "Park Place 9"
print (replace_roman_numerals(s))

产出是：

Park Three
American Tower - Bldg Four
Estancia
Park Place Nine

Answer 1

这将是一种更像python的方法：

conv_map={"1": "One", "I": "One", "2": "Two", "II": "Two", "3": "Three", "III": "Three", "4": "Four", "IV": "Four", "5": "Five", "V": "Five", "6": "Six", "VI": "Six", "7": "Seven", "VII": "Seven", "8": "Eight", "VIII": "Eight", "9": "Nine", "IX": "Nine", "10": "Ten", "X": "Ten"}

def replace_roman_numerals(inputStr, map_=conv_map):
    w = inputStr.split()
    w[-1]=map_.get(w[-1], w[-1])
    return ' '.join(w)

s = "Park III"
s = replace_roman_numerals(s)
print (s)
s = "American Tower - Bldg IV"
print (replace_roman_numerals(s))
s = "Estancia"
print (replace_roman_numerals(s))
s = "Park Place 9"
# in case you'd need it - you can also pass other conversion map:
print (replace_roman_numerals(s, conv_map))

产出：

Park Three
American Tower - Bldg Four
Estancia
Park Place Nine