如何使用Discord bot从channel.history获取消息内容？

Question

我有（想要）打印消息历史记录的代码，但我得到的信息、ID等几乎没有用处

<Message id=x channel=<TextChannel id=x name='general' position=5 nsfw=False news=False category_id=x> type=<MessageType.default: 0> author=<Member id=x name='Cheesebot' discriminator='1916' bot=True nick=None guild=<Guild id=x name='NoLife Minecraft' shard_id=None chunked=False member_count=18>> flags=<MessageFlags value=0>>
<Message id=x channel=<TextChannel id=x name='general' position=5 nsfw=False news=False category_id=x> type=<MessageType.default: 0> author=<User id=x name='' discriminator='3912' bot=False> flags=<MessageFlags value=0>>
<Message id=x channel=<TextChannel id=x name='general' position=5 nsfw=False news=False category_id=x> type=<MessageType.default: 0> author=<Member id=x name='Cheesebot' discriminator='1916' bot=True nick=None guild=<Guild id=x name='NoLife Minecraft' shard_id=None chunked=False member_count=18>> flags=<MessageFlags value=0>>
<Message id=x channel=<TextChannel id=x name='general' position=5 nsfw=False news=False category_id=x> type=<MessageType.default: 0> author=<User id=x name='' discriminator='3912' bot=False> flags=<MessageFlags value=0>>
<Message id=x channel=<TextChannel id=x name='general' position=5 nsfw=False news=False category_id=x> type=<MessageType.default: 0> author=<User id=x name='' discriminator='3912' bot=False> flags=<MessageFlags value=0>>
<Message id=x channel=<TextChannel id=x name='general' position=5 nsfw=False news=False category_id=x> type=<MessageType.default: 0> author=<User id=x name='' discriminator='3912' bot=False> flags=<MessageFlags value=0>>
<Message id=x channel=<TextChannel id=x name='general' position=5 nsfw=False news=False category_id=x> type=<MessageType.default: 0> author=<Member id=x name='Cheesebot' discriminator='1916' bot=True nick=None guild=<Guild id=x name='NoLife Minecraft' shard_id=None chunked=False member_count=18>> flags=<MessageFlags value=0>>
<Message id=x channel=<TextChannel id=x name='general' position=5 nsfw=False news=False category_id=x> type=<MessageType.default: 0> author=<Member id=x name='Cheesebot' discriminator='1916' bot=True nick=None guild=<Guild id=x name='NoLife Minecraft' shard_id=None chunked=False member_count=18>> flags=<MessageFlags value=0>>
<Message id=x channel=<TextChannel id=x name='general' position=5 nsfw=False news=False category_id=x> type=<MessageType.default: 0> author=<User id=x name='' discriminator='3912' bot=False> flags=<MessageFlags value=0>>
<Message id=x channel=<TextChannel id=x name='general' position=5 nsfw=False news=False category_id=x> type=<MessageType.default: 0> author=<Member id=x name='Cheesebot' discriminator='1916' bot=True nick=None guild=<Guild id=x name='NoLife Minecraft' shard_id=None chunked=False member_count=18>> flags=<MessageFlags value=0>>

我现在掌握的代码是：

  async def messagesl(sendc):
    messages = await sendc.history(limit=10).flatten()
    return messages

我需要的是一种获取消息内容和其他信息（如用户等）的方法

敏感信息是一个x（或者对于名称，没有）

Answer 1

只需循环浏览消息并访问所需的属性

messages = await sendc.history(limit=10).flatten()
contents = []

for message in messages:
    contents.append(message.content)

如果你想要一个班轮

contents = [message.content for message in messages]

Answer 2

messages是discord.Message对象的列表。您需要在列表中循环并获取每个列表的Message.content

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参考资料

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