擅长:python、mysql、java
<pre><code> for num in listt:
remainder = target_num - num
remainder_result = howSum(remainder, listt)
if remainder_result is not None:
return remainder_result, num
</code></pre>
<p>由于此代码,操作计数为:2^(300/14)~2^(300/7)
正如你所知,它是递归的</p>