打印输入字谜中字谜和字谜词本身的最大出现次数

Question

a = ['ab', 'absa', 'sbaa', 'basa', 'ba']
res = []
s = 0
for i in range(len(a)):
    b=a[i]
    c = ''.join(sorted(b))
    res.append(c)
res.sort(reverse=False)
wordfreq = [res.count(p) for p in res]
d = dict(zip(res, wordfreq))
all_values = d.values()  #all_values is a list
max_value = max(all_values)
print(max_value)
max_key = max(d, key=d.get)
print(max_key)

在给定的问题中，用户输入各种字谜词，输出应该是该词的最大频率并打印这些字谜词。 如果你能帮我打印输入中的那些字谜，那将非常有帮助

输出：

3 aabs       

预期输出：

3
absa sbaa basa

Answer 1

您可以创建一个单词词典v/s字谜列表

然后打印出字谜列表中包含最多元素的单词

from collections import defaultdict
words = ['ab','absa','sbaa','basa','ba']
wordToAnagram= defaultdict(list) 
# word vs list anagram 
# loop below will create {aabs:  ['absa', 'sbaa', 'basa']}
for word in words:
    s = "".join(sorted(word))
    wordToAnagram[s].append(word)


word, anagrams = max(wordToAnagram.items(), key=lambda x: len(x[1]))
print(" ".join(anagrams))

输出：

3
absa sbaa basa

详细信息

1. 词汇表

在反复阅读单词之后 wordToAnagram(dictionary)看起来像这样

{
"ab" : ["ab", "ba"]
"aabs":  ["absa",  "sbaa", "base"]
}

1. dictionary.items()

items（）返回字典键值的元组对

在哪里,

键：是我们的排序字符串"ab"还是"aabs"

value：是字谜的列表，例如对于key=“ab”，value等于["ab", "ba"]

dict_items([('ab', ['ab', 'ba']), ('aabs', ['absa', 'sbaa', 'base'])])

1. max function using 'key' and lambda expression

max(wordToAnagram.items(), key=lambda x: len(x[1]))

通过比较字谜列表的长度（len(x[1]），从wordToAnagram.items()iterable中查找最大值

Answer 2

您可以尝试使用numpy 和来自statistics模块的mode

import numpy as np
from statistics import mode

words = ['ab','absa','sbaa','basa','ba']

# This sorts the letters of each word, and creates a list of them
sorted_words = [''.join(sorted(word)) for word in words]


max_freq_anagrams = np.array(words)[np.array(sorted_words) == mode(sorted_words)]
# mode(sorted_words) gives you the (sorted) word with the highest frequency
# np.array(sorted_words) == mode(sorted_words) gives you a list of true/false 
# and finaly you slice your words by this true/false list


print(len(max_freq_anagrams))
print(list(max_freq_anagrams))

如果您有多个最频繁的单词，例如。 words = ['ab','absa','sbaa','basa','ba', 'ba']

然后使用max(set(sorted_words), key=sorted_words.count)代替mode(sorted_words)，它取第一个最频繁的单词