Python |如何将值从主列表分组到不同的列表，并为每个索引指定一定的数字范围

Question

OGlist = [A, B, C, D, E, 1, 2, 3, 4, 5, F, G, H, I, J, 6, 7, 8, 9, 10]
_list = []
_list2 = []

所以，我有一个清单。。。我希望OGlist的前5个元素进入_list，第二个5个元素进入_list2，第三个5个元素进入_list，第四个5个元素进入_list2，依此类推

我如何做到这一点

我试过这个：

for x in range(1, len(OGlist) + 1):
    _list.append(OGlist[x-1])
    if x%5 == 0:
        y = x
        while True:
            _list2.append(OGlist[x])
            x += 1
            if x == y + 5:
                break

我应该使用什么条件和逻辑来获得所需的输出

期望输出：

_list = [A, B, C, D, E, F, G, H, I, J]
_list2 = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Answer 1

我会这样处理：

from itertools import chain

_list = list(chain.from_iterable(OGlist[i:i+5] for i in range(0, len(OGlist), 10)))
_list2 = list(chain.from_iterable(OGlist[i:i+5] for i in range(5, len(OGlist), 10)))

OGlist[i:i+5] for i in range(0, len(OGlist), 10)返回类似[[0, 1, 2, 3, 4], [10, 11, 12, 13, 14], ...]的序列，chain.from_iterable将该列表连接到一个列表中

Answer 2

import functools
import operator

OGlist = [A, B, C, D, E, 1, 2, 3, 4, 5, F, G, H, I, J, 6, 7, 8, 9, 10]

groups = list(zip(*(iter(OGlist),)*5))
list_ =  functools.reduce(operator.iconcat, groups[1::2], [])
list_2 = functools.reduce(operator.iconcat, groups[::2], [])

Answer 3

如果您正在寻找一行程序，这应该可以

OGlist = [x, y, foo, bar, etc]

list_of_lists = [OGlist[i:i+5] for i in range(len(OGlist)-5) if i%5==0]

##GETTING LISTS AT EVEN INDEXES
_list = [l_ for i,l_ in enumerate(list_of_lists) if i%2 == 0]

##GETTING LISTS AT ODD INDEXES
_list2 = [l_ for i,l_ in enumerate(list_of_lists) if i%2 == 1]

##FLATTENING
from itertools import chain

_list = list(chain.from_iterable(_list))
_list2 = list(chain.from_iterable(_list2))

它在列表中每隔5个元素（使用OGlist[i:i+5]）（由i%5==0强制）迭代一次，直到到达少于5个元素的点（由len（OGlist）-5强制）

测试：

╰─$ python                                                                                                                                                                  25ms
Python 3.8.3 (default, Jul  2 2020, 11:26:31)
[Clang 10.0.0 ] :: Anaconda, Inc. on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> OGlist = list(range(100))
>>> OGlist
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99]
>>> list_of_lists = [OGlist[i:i+5] for i in range(len(OGlist)-5) if i%5==0]
>>> list_of_lists
[[0, 1, 2, 3, 4], [5, 6, 7, 8, 9], [10, 11, 12, 13, 14], [15, 16, 17, 18, 19], [20, 21, 22, 23, 24], [25, 26, 27, 28, 29], [30, 31, 32, 33, 34], [35, 36, 37, 38, 39], [40, 41, 42, 43, 44], [45, 46, 47, 48, 49], [50, 51, 52, 53, 54], [55, 56, 57, 58, 59], [60, 61, 62, 63, 64], [65, 66, 67, 68, 69], [70, 71, 72, 73, 74], [75, 76, 77, 78, 79], [80, 81, 82, 83, 84], [85, 86, 87, 88, 89], [90, 91, 92, 93, 94]]
>>> _list = [val for val in [l_ for i,l_ in enumerate(list_of_lists) if i%2 == 0]]
>>> _list2 = [val for val in [l_ for i,l_ in enumerate(list_of_lists) if i%2 == 1]]
>>> _list
[[0, 1, 2, 3, 4], [10, 11, 12, 13, 14], [20, 21, 22, 23, 24], [30, 31, 32, 33, 34], [40, 41, 42, 43, 44], [50, 51, 52, 53, 54], [60, 61, 62, 63, 64], [70, 71, 72, 73, 74], [80, 81, 82, 83, 84], [90, 91, 92, 93, 94]]
>>> _list2
[[5, 6, 7, 8, 9], [15, 16, 17, 18, 19], [25, 26, 27, 28, 29], [35, 36, 37, 38, 39], [45, 46, 47, 48, 49], [55, 56, 57, 58, 59], [65, 66, 67, 68, 69], [75, 76, 77, 78, 79], [85, 86, 87, 88, 89]]
>>> from itertools import chain
>>> _list = list(chain.from_iterable(_list))
>>> _list2 = list(chain.from_iterable(_list2))
>>> _list
[0, 1, 2, 3, 4, 10, 11, 12, 13, 14, 20, 21, 22, 23, 24, 30, 31, 32, 33, 34, 40, 41, 42, 43, 44, 50, 51, 52, 53, 54, 60, 61, 62, 63, 64, 70, 71, 72, 73, 74, 80, 81, 82, 83, 84, 90, 91, 92, 93, 94]
>>> _list2
[5, 6, 7, 8, 9, 15, 16, 17, 18, 19, 25, 26, 27, 28, 29, 35, 36, 37, 38, 39, 45, 46, 47, 48, 49, 55, 56, 57, 58, 59, 65, 66, 67, 68, 69, 75, 76, 77, 78, 79, 85, 86, 87, 88, 89]
>>>