如何检查字符串是否包含列表并在python中显示

Question

我有一份清单： lst [a,b,c,d,e]

然后输入： food

我想要输出： there is 1 d

另一个输入示例： aachen

因此，输出为： there is 2 athere is 1 e

它的大小写不重要

Answer 1

Python本机方式：

l = ['a','b','c','d','e']
m = {}
s = input("Enter input string:")
for f in l:
  for k in range(len(s)):
    if f == s[k]:
      if f in m:
        m[f] = m[f] + 1 
      else:
        m[f] = 1

for j in m.keys():
  print(s,"has")
  print(m[j],j)

Answer 2

您可以使用collections.Counter()计算每个字母的出现次数，然后在lst上迭代并输出每个数字出现的次数

import collections

lst = ['a','b','c','d','e']

word = 'food'

word_count = collections.Counter(word)

for letter in lst:
    count = word_count.get(letter)
    if count:
        print(f"There is {count} {letter}")