如何让tic-tac-toe python代码告诉用户他们选择的位置无效，需要选择1到9之间的空格

Question

theBoard = {'7': ' ' , '8': ' ' , '9': ' ' ,
           '4': ' ' , '5': ' ' , '6': ' ' ,
           '1': ' ' , '2': ' ' , '3': ' ' }
 
board_keys = []
 
for key in theBoard:
   board_keys.append(key)

#这将在游戏中每次移动后打印更新的棋盘

def printBoard(board):
    print(board['7'] + ' |' + board['8'] + ' |' + board['9'])
    print('--+--+--')
    print(board['4'] + ' |' + board['5'] + ' |' + board['6'])
    print('--+--+--')
    print(board['1'] + ' |' + board['2'] + ' |' + board['3'])

#这将告诉用户，当他们键入无效输入时，可以选择1到9之间的输入。 def game（）：

   turn = 'X'
   count = 0
   # this prints that its x's or o's turn now and asks where they want to move to.
   for i in range(0, 10 ):
       printBoard(theBoard)
       print("It's your turn " + turn + "  please choose a number between 1 and 9")
       move = input()       
       
       if theBoard [move] == ' ':
           theBoard [move] = turn
           count += 1
       
       else:
           print("this place is already filled " + turn + " where do you want to move to?")
       
           # Now we will check if player X or O has won,for every move after 5 moves. 
       if count >= 5:
           if theBoard['7'] == theBoard['8'] == theBoard['9'] != ' ': # this goes across the top
               printBoard(theBoard)
               print("\ngame ooover\n")               
               print(" yipee " +turn + " won! yoohooo")               
               break
           elif theBoard['4'] == theBoard['5'] == theBoard['6'] != ' ': # this goes across the middle
               printBoard(theBoard)
               print("\ngame oooover\n")               
               print(" yipee " +turn + " won! yoohooo")
               break
           elif theBoard['1'] == theBoard['2'] == theBoard['3'] != ' ': # this goes across the bottom
               printBoard(theBoard)
               print("\ngame ooover\n")               
               print(" yipee " +turn + " won! yoohooo")
               break
           elif theBoard['1'] == theBoard['4'] == theBoard['7'] != ' ': # this goes down the left side
               printBoard(theBoard)
               print("\ngame ooover\n")               
               print(" yipee " +turn + " won! yoohooo")
               break
           elif theBoard['2'] == theBoard['5'] == theBoard['8'] != ' ': # this goes down the middle
               printBoard(theBoard)
               print("\ngame ooover\n")               
               print(" yipee " +turn + " won! yoohooo")
               break
           elif theBoard['3'] == theBoard['6'] == theBoard['9'] != ' ': # this goes down the right side
               printBoard(theBoard)
               print("\ngame oooover\n")               
               print(" yipee " +turn + " won! yoohooo")
               break
           elif theBoard['7'] == theBoard['5'] == theBoard['3'] != ' ': # this goes diagonal
               printBoard(theBoard)
               print("\ngame ooover\n")               
               print(" yipee " +turn + " won! yoohooo")
               break
           elif theBoard['1'] == theBoard['5'] == theBoard['9'] != ' ': # this goes diagonal
               printBoard(theBoard)
               print("\ngame ooover\n")               
               print(" yipee " +turn + " won! yoohooo")
               break
             # \n means create a new line asking the question. 
             # if neither X nor O wins and the board is full, we'll declare the result as 'tie' because well its a tie.
       if count == 9:
           print("\nGame Over\n")               
           print("It's a Tie!!")
           break 
 
        # now we have to change the player after every move so that each player gets a turn.
       if turn =='X':
           turn = 'O'
       else:
           turn = 'X'       
  

现在我们将询问玩家是否希望重新启动游戏，如果是，则游戏将重新启动并再次打印棋盘，如果不是，则游戏将在此结束

   restart = input("would you like to play Again?(yup/nah)")
   if restart == "yup" or restart == "Yup": 
       for key in board_keys:
           theBoard[key] = " "
 
       game()


if __name__ == "__main__":
   game()

这是我所有的代码。每当我输入一个不在1到9之间的数字时，它就会断开并这样说“

Traceback (most recent call last):
  File "main.py", line 123, in <module>
    game()
  File "main.py", line 51, in game
    if theBoard [move] == ' ':
KeyError: '0'"

我试过很多方法，但似乎找不到解决问题的正确方法

Answer 1

确保move变量是int变量类型。它可能是一个字符串，需要转换为int，以便您可以将其用作电路板的索引

下面是一个你可以做到这一点的例子。创建函数getMove()

def getMove():
  got_move = False

  while got_move is False:
    move = input("Enter a number 1-9: ")

    if move.isdigit():
      move = int(move)

      if move <= 9 and move >= 1:
        got_move = True
      else:
        print("\n*** move is out of bounds. Numbers 1-9 only ***\n")
    else:
      print("\n*** Invalid input. Numbers 1-9 only ***\n")

  return move

然后更改分配“移动”的代码，如下所示：

move = getMove()