Selenium中的多线程/多处理

Question

我编写了一个python脚本，从文本文件中提取URL，并从元素中打印出href。然而，我在这里的目标是使它更快，能够在更大范围内使用多处理或多线程处理

在工作流中，每个浏览器进程将从当前url获取href，并在同一浏览器距离中从que加载下一个链接（假设有5个）。当然，每个链接应该被刮1次

示例输入文件：HNlinks.txt

https://news.ycombinator.com/user?id=ingve
https://news.ycombinator.com/user?id=dehrmann
https://news.ycombinator.com/user?id=thanhhaimai
https://news.ycombinator.com/user?id=rbanffy
https://news.ycombinator.com/user?id=raidicy
https://news.ycombinator.com/user?id=svenfaw
https://news.ycombinator.com/user?id=ricardomcgowan

代码：

from selenium import webdriver

driver = webdriver.Chrome()
input1 = open("HNlinks.txt", "r")
urls1 = input1.readlines()

for url in urls1:
    driver.get(url)

    links=driver.find_elements_by_class_name('athing')
    for link in links:
        print(link.find_element_by_css_selector('a').get_attribute("href"))

Answer 1

使用多处理*

注意：我没有在本地测试这个答案。 请尝试并给出反馈：

from multiprocessing import Pool
from selenium import webdriver

input1 = open("HNlinks.txt", "r")
urls1 = input1.readlines()

def load_url(url):
    driver = webdriver.Chrome()
    driver.get(url)
    links=driver.find_elements_by_class_name('athing')
    for link in links:
        print(link.find_element_by_css_selector('a').get_attribute("href"))

if __name__ == "__main__":
    # how many concurrent processes do you want to span? this is also limited by 
    the number of cores that your computer has.
    processes = len(urls1)
    p = Pool(processes ) 
    p.map(load_url, urls1)
    p.close()
    p.join()