我的ifelse语句与我使用的列表不兼容

Question

所以我输入3作为我的眼睛颜色（绿色），它显示“你是一个乐观的人”，而不是“你是一个好奇的人”。为什么会这样？它不是应该显示其他的吗

eyeList = ["blue", "brown","green","hazel","grey","none"]

print(eyeList)

eyecolor = int(input("Pick your eye color: "))

if eyecolor == 1 or 2:

  print("you are a  optimistic person")

else:
  print("you are a curious person")

Answer 1

1. personality可能是string，使用int(input(...))获得int
2. 无法将int与string进行比较
3. 相等运算符是==，而不是=
4. 在每一行if或elif之后都需要冒号:

类似的方法可能会奏效：

myList = ["shy","sociable","loud"]
print(myList)
try :
    personality = int(input("Pick a trait from the list: "))
except ValueError :
    sys.exit("Invalid input: " + str(personality))

if personality == 0 :
  print("You are a person who doesn't doesn't like talking to other people")
elif personality == 1 :
  print("you talk to people, but aren't really loud")
elif personality == 2 :
  print("You love talking to people and you are very loud")

Answer 2

有三个问题：

a）输入作为字符串，您需要在int中转换它

b）检查语法错误，应该是两个等号==

c）跳过if结尾处的:

固定代码：

myList = ["shy","sociable","loud"]
print(myList)
personality = int(input("Pick a trait from the list: "))

if personality == 0:
  print("You are a person who doesn't doesn't like talking to other people")
elif personality == 1:
  print("you talk to people, but aren't really loud")
elif personality == 2:
  print("You love talking to people and you are very loud")

Answer 3

Python语法：

if condition:
    Indented expressions
elif condition2:
    Other expressions
else:
    Further expressions

您只是缺少每个条件之后的冒号（:）

此外，要检查某物是否等于其他某物，必须使用==。单个=执行赋值

if variable == 42:
    variable = 7

最后，不能将整数与字符串进行比较（input()函数返回字符串）。要执行此操作，请将字符串转换为整数：

IntegerValue = int(stringFormat)

最后提示：您的控制台为您提供了有关代码错误的有用提示。听他们说