如何在Python上获取字典中的匹配子字符串键并返回相应的值？

Question

python新手，还有很多东西需要学习！我正在尝试使用用户输入的子字符串键返回字典（plantdict）值。下面是到目前为止我的代码

 def search_plant_name():
    while True:
        enter_plant_name = input('Please enter plant name: ').capitalize()
        filtered_dict_key = [key for (key, val) in plantdict.items() if enter_plant_name in key]
        filtered_dict_time = [val[0] for (key, val) in plantdict.items() if enter_plant_name in key]
        filtered_dict_info = [val[1:] for (key, val) in plantdict.items() if enter_plant_name in key]
        if ##NOT SURE WHAT TO WRITE HERE## in plantdict.items():
            print('Plant name:', str(filtered_dict_key).strip("[]").replace("'",""))
            print('Date and time of entry/revision of plant record:', str(filtered_dict_time).strip("[]").replace("'",""))
            print('Information of plant:')
            print('Date and time of entry/revision of plant record:', str(filtered_dict_info).strip("[]").replace("'",""))
        else:
            provide_option_2 = user_input_options('The plant does not exist, would you like to add in the record? (Y / N): ')
            if provide_option_2 in ('Y'):
                print('OPTION2')
                ##CREATE FUNCTION FOR OPTION 2##

其思想是，例如，如果用户键入“roses”，而我的字典中有“Red roses”作为键，它将返回该键的相应值。但是，如果用户键入的单词/短语与我的任何键都不匹配，那么他/她可以选择将植物详细信息添加到词典中，因此选择2

我不知道我做错了什么，或者可能遗漏了什么。任何帮助都将不胜感激！多谢各位

Answer 1

筛选的dict键是一个列表，而不是一个字符串。strip（）不是对列表有效的操作，只是对字符串有效。括号：“[]”不是字符串-它们对python有不同的含义

您的while循环也将永远运行，但我认为这不是当前的问题

只需编写自己的for循环，而不是编写列表理解（“[i for i in l if i==v]”）。列表理解无论如何都会循环

def search_plant_name():
    keep_going = True
    while keep_going:
        enter_plant_name = input('Please enter plant name: ').capitalize()
        for key, val in plantdict.items():
            if enter_plant_name in key:
                print("Plant name: " + key)
                print("Date and time of entry/revision of plant record: " + val[0])
                print('Information of plant:')
                print('Date and time of entry/revision of plant record: ' + val[1])
                keep_going = False  # or put this wherever you want to exit while loop
            else:
                provide_option_2 = user_input_options('The plant does not exist, would you like to add in the record? (Y / N): ')
                if provide_option_2 in ('Y'):
                    print('OPTION2')
                    ##CREATE FUNCTION FOR OPTION 2##