我有下一个Python代码:
tubby_output=model.output[:,281]
last_conv_layer=model.get_layer('block5_conv3'))
with tf.GradientTape() as tape:
grads = tape.gradient(tubby_output, last_conv_layer.output)
pooled_grads = K.mean(grads, axis=(0,1,2))
iterate = K.function([model.input],
[pooled_grads, last_conv_layer.output[0]])
pooled_grads_value, conv_layer_output_value = iterate([img_tensor])
for i in range(512):
conv_layer_output_value[:, :, i] *= pooled_grads_value[i]
heatmap = np.mean(conv_layer_output_value, axis=-1)`
我得到以下错误:
<ipython-input-128-5b66da230a26> in <module>
13 # Вектор с формой (512,), каждый элемент которого определяет
14 # интенсивность градиента для заданного канала в карте признаков
---> 15 pooled_grads = K.mean(grads, axis=(0,1,2))
17 iterate = K.function([model.input],
c:\users\79278\appdata\local\programs\python\python38\lib\site-packages\tensorflow\python\keras\backend.py in mean(x, axis, keepdims)
2112 A tensor with the mean of elements of `x`.
2113 """
-> 2114 if x.dtype.base_dtype == d types_module.bool:
2115 x = math_ops.cast(x, floatx())
2116 return math_ops.reduce_mean(x, axis, keepdims)
AttributeError: 'None Type' object has no attribute 'dtype'
帮我解决这个问题!谢谢
目前没有回答
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