擅长:python、mysql、java
<pre><code>for row in df:
</code></pre>
<p>你不能以这种方式对熊猫进行迭代</p>
<p>像这样试试iloc</p>
<pre><code>def bad_loan(df):
for i in range(len(df)):
row = df.iloc[i]
status = row['bad_loan']
name = row['name_client']
if status == 'Yes':
for n in df:
name_client = df['name_client']
if name == name_client:
df['bad_loan'] = 'Yes'
else:
df['bad_loan'] = 'No'
bad_loan(df)
</code></pre>