如何隐藏内部错误堆栈[python]

Question

在下面的代码中，我希望防止显示内部错误回溯。 （在lua中，等效值为error("info",2)）

在Python中也可以这样做吗

def asd():
  def efe(number = 2):
    try:
      number += 2
      print(number)
    except TypeError as e:
      failed = True
#      raise TypeError() # makes it even worse
    if failed:
      raise TypeError() # dont show internal stuff please
      # raise TypeError().with_traceback() # i guess use this is the way

  efe(number = "asd") # i want the end of Error Stack here

asd()

印刷品

Traceback (most recent call last):
  File "main.py", line 15, in <module>
    asd()
  File "main.py", line 13, in asd
    efe(number = "asd") # i want the end of Error Stack here
  File "main.py", line 10, in efe
    raise TypeError() # dont show internal stuff please
TypeError

Answer 1

我认为这在python中是不可能的。不过，您可以将一个“错误”作为纯文本输出

编辑：尝试使用traceback模块格式化错误消息