擅长:python、mysql、java
<p>我认为你需要自己把它弄平,幸好它并不复杂:</p>
<pre><code>s = [[k, i, *j.values()] for k,v in data["reports"].items() for i, j in v.items()]
print (pd.DataFrame(s))
0 1 2 3
0 Google-Pixel 2 XL -MIoCtD9YUF2G9Esfrfz 04 Oct 2020 23:25:17:047 onCreate MainActivity 1601825117067
1 Google-Pixel 2 XL -MIoCtFVOxu8wdEHtm6q 04 Oct 2020 23:25:17:214 onCreate Service 1601825117216
2 Google-Pixel 2 XL -MIoCyBtKMQqQzUHEXsW 04 Oct 2020 23:25:37:682 onStartCommand Service 1601825137685
3 Google-Pixel 2 XL -MIoFWll9r3qwzWNoGMn 04 Oct 2020 23:36:47:687: (1.3212517, 103.860314) 1601825807693
4 Vivo 1820 -MIoF14JUm6JMZrOzDlL 04 Oct 2020 23:34:37:623 onCreate MainActivity 1601825677653
5 Vivo 1820 -MIoF1A9ZZNqTu5W-rQD 04 Oct 2020 23:34:38:016 onCreate Service 1601825678026
6 Vivo 1820 -MIoF2gNDua9FfLBTg6q 04 Oct 2020 23:34:44:235 onCreate MainActivity 1601825684248
</code></pre>