如何修复溢出错误：int太大而无法转换为浮点错误？

Question

def factorial(n):
    if n == 1:
        return n
    else:
        return n*factorial(n-1)


def sin(x):
    OddNumber = 3
    counter = 1
    NumberOfTerms = 80
    while counter < NumberOfTerms:
        x -= (x**OddNumber)/(factorial(OddNumber))
        OddNumber += 2
        counter += 1
        x += (x**OddNumber)/(factorial(OddNumber))
        OddNumber += 2
        counter += 1
    return x


theta = float(input("input angle in degrees: "))
theta = float((theta*math.pi/180))
print(sin(theta))

这是我用来寻找x角sin近似值的代码。我想增加变量NumberOfTerms来提高精度，但当我这样做时，我得到了这个错误

OverflowError: int too large to convert to float

我怎样才能避开这件事？有没有办法绕过这个问题

Answer 1

当您使用倒数阶乘值时，代码可以很好地处理较高的NumberOfTerms

import math

def reciproc_factorial(n):
    if n == 1:
        return n
    else:
        return 1/n*reciproc_factorial(n-1)


def sin(x):
    OddNumber = 3
    counter = 1
    NumberOfTerms = 150
    while counter < NumberOfTerms:
        x -= (x**OddNumber) * (reciproc_factorial(OddNumber))
        OddNumber += 2
        counter += 1
        x += (x**OddNumber) * (reciproc_factorial(OddNumber))
        OddNumber += 2
        counter += 1
    return x


theta = 23
theta = float((theta*math.pi/180))
print(sin(theta))