Python尽可能高效地将字节转换为字符串字典

Question

我正在尝试高效（快速）地将字节文件转换成字典。 到目前为止，我已经把它解码成str，去掉{}并把它编入字典。但是我仍然得到单字符串引号，所以我不能按键调用dict。我该怎么做

response = b'{"address":"david@gmail.com","username":"david","domain":"gmail.com","md5Hash":"f3c52e5ef3d2b471d0ef51c66c21d10c","suggestion":"","validFormat":true,"deliverable":false,"fullInbox":false,"hostExists":true,"catchAll":false,"gravatar":false,"role":false,"disposable":false,"free":true}'

到目前为止，我采取了以下步骤：

print(response.decode("utf-8"))

{"address":"david@gmail.com","username":"david","domain":"gmail.com","md5Hash":"f3c52e5ef3d2b471d0ef51c66c21d10c","suggestion":"","validFormat":true,"deliverable":false,"fullInbox":false,"hostExists":true,"catchAll":false,"gravatar":false,"role":false,"disposable":false,"free":true}



print({response.decode("utf-8").replace("}","").replace("{","")})

{'"address":"david@gmail.com","username":"david","domain":"gmail.com","md5Hash":"f3c52e5ef3d2b471d0ef51c66c21d10c","suggestion":"","validFormat":true,"deliverable":false,"fullInbox":false,"hostExists":true,"catchAll":false,"gravatar":false,"role":false,"disposable":false,"free":true'}

但是由于'，我仍然无法按键调用dict。
我需要这是快速的，资源不足

Answer 1

就像@juanpa.arrivillaga说的那样，只需使用json模块

在这里：

import json
d = json.loads(response)

现在d的值是您解码的dict

同样像@juanpa.arrivillaga所说的，没有必要使用.decode()，json.loads()可以对字节进行操作