在python中将两个数组与JSON对象作为项目进行比较的最佳方法

Question

您有两个数组（伪值），其中JSON对象作为数组中的每个项：

ArrayOne：

[{'keyboards': '1'}, {'keyboards': '2'}, {'keyboards': '3'}, {'mice': '1'}]

阵列2：

[{'keyboards': '1'}, {'keyboards': '2'}, {'mice': '1'}]

我想同时循环遍历每个数组，如果arrayOne中有一个值存在于arrayTwo中，但不存在于arrayTwo中，则将其标记（做点什么）

这是我的代码示例：

for deviceAndID in ArrayOne:
        if deviceAndID in ArrayTwo:
             print("It exists in both arrays")
        else:
             print("Device " + str(deviceAndID) + "is not in arrayTwo")

在这个代码示例中，它为最大数组中的每个值打印出（示例）Device {'keyboard': '1'} is not in arrayTwo

实际上，我需要它根据上面的两个数组打印出以下内容：

It exists in both arrays
It exists in both arrays
Device {'keyboard': '3'} is not in arrayTwo
It exists in both arrays

我觉得这个问题是由每个元素或项都是json对象这一事实引起的，那么考虑到它们是列表中的json对象，我该如何处理呢

Answer 1

这是我根据你的问题得出的结论：

>>> ArrayOne = [{'keyboards': '1'}, {'keyboards': '2'}, {'keyboards': '3'}, {'mice': '1'}]
>>> ArrayTwo = [{'keyboards': '1'}, {'keyboards': '2'}, {'mice': '1'}]
>>> for deviceAndID in ArrayOne:
        if deviceAndID in ArrayTwo:
             print("It exists in both arrays")
        else:
             print("Device " + str(deviceAndID) + "is not in arrayTwo")

             
It exists in both arrays
It exists in both arrays
Device {'keyboards': '3'}is not in arrayTwo
It exists in both arrays