我有一个如下所示的数据框:
USUBJID IDVAR IDVARVAL QNAM QVAL
0 Dummy-01-0001 AESEQ 1.0 AEdummy1 2012-02-15
1 Dummy-01-0002 AESEQ 1.0 AEdummy1 2012-02-23
2 Dummy-01-0004 AESEQ 1.0 AEdummy1 2012-02-06
3 Dummy-01-0004 AESEQ 2.0 AEdummy1 2012-03-10
4 Dummy-01-0005 AESEQ 1.0 AEdummy1 2012-03-10
5 Dummy-01-0001 AESPID 1 dummy2AE Gastrointestinal disorders
6 Dummy-01-0002 AESPID 1 dummy2AE Nervous system disorder
7 Dummy-01-0004 AESPID 2 dummy2AE Gastrointestinal disorders
8 Dummy-01-0004 AESPID 1 dummy2AE Nervous system disorder
9 Dummy-01-0005 AESPID 1 dummy2AE Gastrointestinal disorders
上面的dataframe只是一个示例,请使用下面的代码在dataframe中获取更多数据
df = pd.DataFrame({'USUBJID': {0: 'Dummy-01-0001', 1: 'Dummy-01-0002', 2: 'Dummy-01-0004', 3: 'Dummy-01-0004', 4: 'Dummy-01-0005', 5: 'Dummy-01-0007', 6: 'Dummy-01-0008', 7: 'Dummy-01-0008', 8: 'Dummy-01-0010', 9: 'Dummy-01-0010', 10: 'Dummy-01-0011', 11: 'Dummy-01-0011', 12: 'Dummy-01-0013', 13: 'Dummy-01-0013', 14: 'Dummy-01-0014', 15: 'Dummy-01-0016', 16: 'Dummy-01-0016', 17: 'Dummy-01-0019', 18: 'Dummy-01-0001', 19: 'Dummy-01-0002', 20: 'Dummy-01-0004', 21: 'Dummy-01-0004', 22: 'Dummy-01-0005', 23: 'Dummy-01-0007', 24: 'Dummy-01-0008', 25: 'Dummy-01-0008', 26: 'Dummy-01-0010', 27: 'Dummy-01-0010', 28: 'Dummy-01-0011', 29: 'Dummy-01-0011', 30: 'Dummy-01-0013', 31: 'Dummy-01-0013', 32: 'Dummy-01-0014', 33: 'Dummy-01-0016', 34: 'Dummy-01-0016', 35: 'Dummy-01-0017', 36: 'Dummy-01-0017', 37: 'Dummy-01-0019'}, 'IDVAR': {0: 'AESEQ', 1: 'AESEQ', 2: 'AESEQ', 3: 'AESEQ', 4: 'AESEQ', 5: 'AESEQ', 6: 'AESEQ', 7: 'AESEQ', 8: 'AESEQ', 9: 'AESEQ', 10: 'AESEQ', 11: 'AESEQ', 12: 'AESEQ', 13: 'AESEQ', 14: 'AESEQ', 15: 'AESEQ', 16: 'AESEQ', 17: 'AESEQ', 18: 'AESPID', 19: 'AESPID', 20: 'AESPID', 21: 'AESPID', 22: 'AESPID', 23: 'AESPID', 24: 'AESPID', 25: 'AESPID', 26: 'AESPID', 27: 'AESPID', 28: 'AESPID', 29: 'AESPID', 30: 'AESPID', 31: 'AESPID', 32: 'AESPID', 33: 'AESPID', 34: 'AESPID', 35: 'AESPID', 36: 'AESPID', 37: 'AESPID'}, 'IDVARVAL': {0: '1.0', 1: '1.0', 2: '1.0', 3: '2.0', 4: '1.0', 5: '1.0', 6: '1.0', 7: '2.0', 8: '1.0', 9: '2.0', 10: '1.0', 11: '2.0', 12: '1.0', 13: '2.0', 14: '1.0', 15: '1.0', 16: '2.0', 17: '1.0', 18: '1', 19: '1', 20: '2', 21: '1', 22: '1', 23: '1', 24: '1', 25: '2', 26: '2', 27: '1', 28: '1', 29: '2', 30: '1', 31: '2', 32: '1', 33: '1', 34: '2', 35: '1', 36: '2', 37: '1'}, 'QNAM': {0: 'AEdummy1', 1: 'AEdummy1', 2: 'AEdummy1', 3: 'AEdummy1', 4: 'AEdummy1', 5: 'AEdummy1', 6: 'AEdummy1', 7: 'AEdummy1', 8: 'AEdummy1', 9: 'AEdummy1', 10: 'AEdummy1', 11: 'AEdummy1', 12: 'AEdummy1', 13: 'AEdummy1', 14: 'AEdummy1', 15: 'AEdummy1', 16: 'AEdummy1', 17: 'AEdummy1', 18: 'dummy2AE', 19: 'dummy2AE', 20: 'dummy2AE', 21: 'dummy2AE', 22: 'dummy2AE', 23: 'dummy2AE', 24: 'dummy2AE', 25: 'dummy2AE', 26: 'dummy2AE', 27: 'dummy2AE', 28: 'dummy2AE', 29: 'dummy2AE', 30: 'dummy2AE', 31: 'dummy2AE', 32: 'dummy2AE', 33: 'dummy2AE', 34: 'dummy2AE', 35: 'dummy2AE', 36: 'dummy2AE', 37: 'dummy2AE'}, 'QVAL': {0: '2012-02-15', 1: '2012-02-23', 2: '2012-02-06', 3: '2012-03-10', 4: '2012-03-10', 5: '2012-02-08', 6: '2012-03-18', 7: '2012-03-07', 8: '2012-02-01', 9: '2012-01-10', 10: '2012-01-19', 11: '2012-03-28', 12: '2012-02-19', 13: '2012-02-14', 14: '2012-03-13', 15: '2012-03-08', 16: '2012-02-05', 17: '2012-03-18', 18: 'Gastrointestinal disorders', 19: 'Nervous system disorder', 20: 'Gastrointestinal disorders', 21: 'Nervous system disorder', 22: 'Gastrointestinal disorders', 23: 'Vascular disorders', 24: 'Gastrointestinal disorders', 25: 'Vascular disorders', 26: 'Nervous system disorder', 27: 'Gastrointestinal disorders', 28: 'Nervous system disorder', 29: 'Nervous system disorder', 30: 'Nervous system disorder', 31: 'Gastrointestinal disorders', 32: 'Gastrointestinal disorders', 33: 'Vascular disorders', 34: 'Gastrointestinal disorders', 35: 'Nervous system disorder', 36: 'Nervous system disorder', 37: 'Vascular disorders'}})
让我们稍微了解一下结构IDVAR
保存变量名IDVARVAL
保存其值QNAM
保存另一个变量名QVAL
保存相应的值。
这个结构,在我工作的领域中叫做规范化结构,我知道这很奇怪
我希望以以下形式获取此数据:
USUBJID AESEQ AESPID AEdummy1 dummy2AE
0 Dummy-01-0001 1.0 1 2012-02-15 Gastrointestinal disorders
1 Dummy-01-0002 1.0 1 2012-02-23 Nervous system disorder
2 Dummy-01-0004 1.0 2 2012-02-06 Gastrointestinal disorders
3 Dummy-01-0004 2.0 1 2012-03-10 Nervous system disorder
4 Dummy-01-0005 1.0 1 2012-03-10 Gastrointestinal disorders
如果我必须只为QNAM
和QVAL
做这件事,没有问题,我可以使用pandas的pivot轻松完成,如下所示:
df.pivot(
index=['USUBJID', 'IDVARVAL', 'IDVAR'],
columns='QNAM',
values='QVAL'
).reset_index()
即使对于这个问题,我也可以使用某种掩蔽,但我知道这不是最有效的方法,因为这些数据将有数千条甚至数百万条记录
请注意:USUBJID
和IDVARVAL
对于IDVAR
的组合应该映射到QNAM
的QVAL
值。也就是说,对于输出数据帧,AESEQ
、AESPID
、AEdummy1
和dummy2AE
的一些记录可能是NaN或空的。换句话说,对于上面的示例,Dummy-01-0001
和AESEQ=1.0
唯一地标识AEdummy1 = 2012-02-15
让我们尝试使用
unstacking
后跟concat
:解释
将数据帧分组到
IDVAR
上,并使用cumcount
创建顺序计数器,以唯一标识每个IDVAR
组的行,然后将此计数器与列USUBJID
一起设置为数据帧的索引:现在,对于每个列
IDVARVAL
和QVAL
通过追加相应的列IDVAR
和QNAM
来更新索引,然后unstack
来重新塑造:最后,
concat
将上述未堆叠的帧s1
和s2
沿axis=1
移动以获得所需的结果:您可以使用pyjanitor中的pivot_longer重塑数据,使用cumcount创建计数器以创建唯一索引pivot数据,并进行一些最终清理以获得与预期输出类似的结果:
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