PyQt如何在closeEvent中获取发送方(widget)?

2024-10-01 09:27:22 发布

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我试图为几个动态添加到QMainWindow的dockWidget捕捉closeEvent。我不清楚我怎样才能知道哪个小部件被关闭了。。下面是一个简化的例子:

class Example(QtGui.QMainWindow):

    def __init__(self):
        super(Example, self).__init__()

        self.leftDockWidget = QtGui.QDockWidget('pick tool', self)
        self.leftDockWidget.setWidget( QtGui.QLabel('a dock widget') )
        self.addDockWidget( QtCore.Qt.LeftDockWidgetArea, self.leftDockWidget )
        self.leftDockWidget.closeEvent = self.dockWidgetCloseEvent       
        self.show()

    def dockWidgetCloseEvent(self, event):
        print event
        # how to get sender widget ?    

在事件.发送者()似乎不存在。。 有什么想法吗?在

谢谢


Tags: selfeventinit部件exampledef动态widget
2条回答

实现目标的一种方法是使用event filter

from PyQt4 import QtGui, QtCore

class Example(QtGui.QMainWindow):
    def __init__(self):
        super(Example, self).__init__()
        self.leftDockWidget = QtGui.QDockWidget('pick tool', self)
        self.leftDockWidget.setWidget(QtGui.QLabel('a dock widget'))
        self.addDockWidget(QtCore.Qt.LeftDockWidgetArea, self.leftDockWidget)
        self.leftDockWidget.installEventFilter(self)

    def eventFilter(self, source, event):
        if (event.type() == QtCore.QEvent.Close and
            isinstance(source, QtGui.QDockWidget)):
            print source.windowTitle()
        return super(Example, self).eventFilter(source, event)

if __name__ == '__main__':

    import sys
    app = QtGui.QApplication(sys.argv)
    window = Example()
    window.show()
    sys.exit(app.exec_())
def dockWidgetCloseEvent(self, event):
    self.sender()

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