如果元组的第一个项等于任何给定字符串，则从列表中删除元组

Question

我的清单如下：

device = [('nvme2n1',), 
          ('nvme1n1', '/local'), 
          ('nvme0n1',), 
          ('nvme0n1p1', '/'),
          ('nvme0n1p128',), 
          ('nvme3n1',)]

我想从包含nvme1n1或nvme0n1p1或nvme0n1p128或nvme0n1的列表中删除几个元组

因此，最终的名单将有

final_device = [('nvme2n1',),('nvme3n1',)]

按以下方式尝试，但不起作用&；获取错误"AttributeError: 'tuple' object has no attribute 'startswith'"

for word in devices[:]: 
    if word.startswith("nvme0n1","nvme0n1p1","nvme0n1p128"): 
        devices.remove(word)

有人能帮忙吗

Answer 1

在devices列表中迭代的word是元组。您需要访问您感兴趣的元组的该部分，如下所示：

for word in devices[:]: 
    if word[0] in ["nvme0n1","nvme0n1p1","nvme0n1p128"]: 
        devices.remove(word)