回答此问题可获得 20 贡献值,回答如果被采纳可获得 50 分。
<p>有两个列表</p>
<p>相同数量的元素(浮动)</p>
<p>具有步数的int变量</p>
<p>是否有一个命令或命令可以使第一个值到第二个值的范围</p>
<pre><code>divider = 12
startValues= [0.9, 0.3, 0.8, 0.9]
endValues = [0.6, 1.0, 1.0, 0.4]
#the result should look like this:
#incrementalValues = [0.025, 0.05833, 0.0166, 0.04166]
#startValues = [0.9, 0.3, 0.8, 0.9 ]
#intermediaryVal = [0.875, 0.35833, 0.8166, 0.85834 ]
#intermediaryVal = [0.85, 0.4166, 0.8333, 0.81668 ]
#intermediaryVal = [0.825, 0.4749, 0.8500, 0.77502 ]
#intermediaryVal = [0.8, 0.5333, 0.8666, 0.73336 ]
#intermediaryVal = [0.775, 0.5916, 0.8833, 0.6917 ]
#intermediaryVal = [0.75, 0.6499, 0.9000, 0.65004 ]
#intermediaryVal = [0.725, 0.7083, 0.9166, 0.60838 ]
#intermediaryVal = [0.7, 0.7666, 0.9333, 0.56672 ]
#intermediaryVal = [0.675, 0.8249, 0.9500, 0.52506 ]
#intermediaryVal = [0.65, 0.8833, 0.9666, 0.4834 ]
#intermediaryVal = [0.625, 0.9416, 0.9833, 0.44174 ]
#endValues = [0.6, 1.0, 1.0, 0.4 ]
</code></pre>