擅长:python、mysql、java
<p>您可以尝试以下方法:</p>
<pre><code>np.concatenate([x.ravel() for x in myarrs])
</code></pre>
<p>这应该比您的方法更快:</p>
<pre><code>a = np.arange(9).reshape(3,3)
b = np.arange(25).reshape(5,5)
c = np.arange(4).reshape(2,2)
myarrs = [a,b,c]
res = np.concatenate([x.ravel() for x in myarrs])
print(res)
# [ 0 1 2 3 4 5 6 7 8 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 0 1 2 3]
%timeit np.concatenate([x.ravel() for x in myarrs])
# 100000 loops, best of 3: 2.47 µs per loop
%timeit np.concatenate(list(map(lambda x: x.ravel(), myarrs)))
# 100000 loops, best of 3: 2.85 µs per loop
%timeit np.concatenate([x.flatten() for x in myarrs])
# 100000 loops, best of 3: 3.69 µs per loop
%timeit np.hstack([x.ravel() for x in myarrs])
# 100000 loops, best of 3: 5.69 µs per loop
%timeit np.hstack([np.hstack(i) for i in myarrs])
# 10000 loops, best of 3: 29.1 µs per loop
</code></pre>